6.16
s = si + a G b (r)1/2 (1)
Given: r = C / d (2)
where C = constant and d = grain size.
Substituting (2) into (1) gives:
s = si + a G b (C / d)1/2 (3)
which is s = si
+ a G b C1/2 (d)-1/2
and is the same form as the Hall-Petch type equation:
s = si + k (d)-1/2 where k = a G b C1/2 Q.E.D.
[cf. pp.274-275]
6.18
Given:
s = 25 + 200 e 0.5 for which s0 = 25 MPa and K = 200 MPa [Holloman-Ludmick eq.]
Find: Energy of deformation/unit volume corresponding to uniform strain, eu.
U = ò s de + constant [ the definite intergral is from e = 0 to e = eu .
U = s0 e1 + (K e1n+1 ) / 2 =
25MPa
(0.5) +
(200MPa 0.51.5 ) / 2
because at eu, eu = n.
U = (25 + 35.4) · 106 N/m2 = 6 · 107 J/ m2