6.16

 

s = si + a G b (r)1/2                                                   (1)

 

Given: r = C / d                                                           (2)

where C = constant and d = grain size.

 

Substituting (2) into (1) gives:

 

s = si + a G b (C / d)1/2                                              (3)

 

which is s = si + a G b C1/2 (d)-1/2

 

and is the same form as the Hall-Petch type equation:

 

s = si + k (d)-1/2    where k = a G b C1/2                              Q.E.D.

 

[cf. pp.274-275]

 

 

 

6.18

 

Given:

s = 25 + 200 e 0.5         for which s0 = 25 MPa and K = 200 MPa [Holloman-Ludmick eq.]

 

Find:  Energy of deformation/unit volume corresponding to uniform strain, eu.

 

U = ò s de  + constant  [ the definite intergral is from e = 0 to e = eu .

 

U = s0 e1 + (K e1n+1 ) / 2  = 25MPa   (0.5) + (200MPa   0.51.5 ) / 2  because at eu, eu = n.

 

U = (25 + 35.4) · 106  N/m2     = 6  · 107 J/ m2